Find the initial velocity of a car which is stopped in 10 sec by applying breaks.The retardation due to break is -2.5m/s*
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initial velocity- ?
final velocity-0
acceleration- (-2.5m/sec)
on first equation of motion -
v=u+at
0=u-2.5×10
0=u-25
u=25m/sec
final velocity-0
acceleration- (-2.5m/sec)
on first equation of motion -
v=u+at
0=u-2.5×10
0=u-25
u=25m/sec
Answered by
0
initial velocity is, 25 m/sec
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