a car starts from rest and moves with an acceleration of 5m/s^2. if it continous with a constant velocity then what distance does it cover in 12min with reespect to the starting point
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For how much time the car has been accelerated before it continues the constant motion . Please correct your question and ask again.
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For how much time the car has been accelerated before it continues the constant motion . Please correct your question and ask again.
Thanks.
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so, v = 0+ 5×8=40 m / s
s = ut+1/2at^2=0+1/2×5×8×8=160 m
now t =4 sec (12-8 sec) , v =40 m/s
as motion is constant so, s = vt =40×4=160m
so, total distance= 160+160=320 m from rest
....maybe it can help...
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