Find the initial velocity of a car which is stopped in 10s by applying brakes. Retardation due to brakes is 2.5 m/s2
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Answered by
5
Final Velocity of the car=0
Retardation=2.5m/s(square)
Time taken to stop=10secs
By first eq of motion, we know, V=U +AT
=0=u+(-2.5×10)
=0=u-25
=U=0+25=25
HOPE IT HELPS
Retardation=2.5m/s(square)
Time taken to stop=10secs
By first eq of motion, we know, V=U +AT
=0=u+(-2.5×10)
=0=u-25
=U=0+25=25
HOPE IT HELPS
Answered by
1
Answer:
Initial velocity = 25 m/s
Explanation:
Time = 10 sec, Retardation = -2.5 m/s^2 and Final velocity = 0 m/s
v = u + at (First Equation Of Motion)
0 = u + (-2.5)(10)
0 = u - 25.0
-u = -25.0
u = 25 m/s
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