Find the initial velocity of a car which is stopped in 4 seconds by applying brakes.The retardation due to brakes is 5m/s square.
Answers
Answered by
5
Given that,
The deceleration, a = 5m\s^2
time, t = 4 s
Last velocity, v = 0 {the car stopped in last}
The initial velocity, u = ?
We know,
v= u - at { it is deceleration}
or, u - at= v
or, u = at { v=0}
so, u= 5×4
= 20 [answer]
The deceleration, a = 5m\s^2
time, t = 4 s
Last velocity, v = 0 {the car stopped in last}
The initial velocity, u = ?
We know,
v= u - at { it is deceleration}
or, u - at= v
or, u = at { v=0}
so, u= 5×4
= 20 [answer]
Answered by
2
Explanation:
Answer ⤵️
Initial velocity, u=?
Final velocity, v=0m/s (car is stopped)
Acceleration, a=−2.5m/s
2
(negative because it is retardation)
Time, t=10s
Use the relation of the first equation of motion:
v=u+at
0=u+(−2.5)×10
u=25m/s
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