Find the initial velocity of a car which stopped in 10 seconds by applying brakes. The retardation due to brake is 2.5m/s2
Answers
Answered by
6
Bonjour ❤
Here's Your Answer
>>--------☺--------<<
v = 0
a = 2.5 m/s2
t = 10 sec
u = ?
according to first equation of motion,
v = u + at
0 = u + 2.5×10
0 = u + 25
u = -25
initial velocity of car is -25 m/s....
>>--------☺--------<<
hope it will help you :)✌✌
Here's Your Answer
>>--------☺--------<<
v = 0
a = 2.5 m/s2
t = 10 sec
u = ?
according to first equation of motion,
v = u + at
0 = u + 2.5×10
0 = u + 25
u = -25
initial velocity of car is -25 m/s....
>>--------☺--------<<
hope it will help you :)✌✌
jenish85:
thanks
Answered by
2
Here is your answer
here,
v= 0m/s
t= 10 secs
a= -2.5m/s^2 (since retardation is negative acceleration)
by equation of motion
v = u + at
0 = u + (-2.5 × 10)
0 = u - 25 m/s
u = 25 m/s
So, initial velocity of car is 25 m/s
here,
v= 0m/s
t= 10 secs
a= -2.5m/s^2 (since retardation is negative acceleration)
by equation of motion
v = u + at
0 = u + (-2.5 × 10)
0 = u - 25 m/s
u = 25 m/s
So, initial velocity of car is 25 m/s
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