Question

find the initial velocity of a car with the stopped in 10 seconds by applying brakes the retardation due to brakes is 2.5 M second square

Answer 1

The formula for stopping distance is
s= (initial velocity)² ÷2a
Now by applying v=u+at
v=0, t is 10 and a is 2.5 we get the value of u which is 25 m per sec.
Now put value in stopping distance formula of stopping distance
We get s= 125m