find the innisial velocity of a car which is stopped in 10 second why applying breaks the redardation due to breaks 2.5 sqare
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first of all write all the given values
t = 10s
a = -2.5 (since it is retardation)
v = 0 (because after applying the brakes the car will stop))
we know that
v = u + at
0 = u + (-2.5) (10)
0 = u - 25
u = 25m/s
is the answer
t = 10s
a = -2.5 (since it is retardation)
v = 0 (because after applying the brakes the car will stop))
we know that
v = u + at
0 = u + (-2.5) (10)
0 = u - 25
u = 25m/s
is the answer
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