Question

Find the instantaneous acceleration of a truck, at time t = 6 seconds, moving with the velocity
v given by, v = 3t3 + 4t2 + 5t + 6

Answer 1

Answer:

a = dv/dt = d(3t³+4t²+5t+6)/dt

= 9t²+8t+5

Now we know t = 6sec

So, a = 9(6)²+8×6+5

= 324+48+5

= 377 m/s²

So instantaneous acceleration = 377m/s²