Find the instantaneous velocity of the particle for position x= 2t²-6t+3 for time t=5.28 se
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Answered by
0
Answer:
X=2t2 - 6t +3
Dx/dt=4t-6+0
V=4*5.28 - 6
=21.12-6
15.12m/s
Answered by
0
Answer:
x=2t^2-6t+3
dx/dt=v=4t-6
So, instantaneous velocity=4(5.28)-6
=21.12-6=15.12
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