Question

Find the instantaneous velocity of the particle for position x= 2t²-6t+3 for time t=5.28 se

Answer 1

Answer:

X=2t2 - 6t +3

Dx/dt=4t-6+0

V=4*5.28 - 6

=21.12-6

15.12m/s

Answer 2

Answer:

x=2t^2-6t+3

dx/dt=v=4t-6

So, instantaneous velocity=4(5.28)-6

=21.12-6=15.12