Question

find the integral of (y^2 - 1 ) dx - 2dy = 0​

Answer 1

Answer:

I CANT UNDERSTAND YOUR QUESTION

Step-by-step explanation:

SO , SORRY I CAN'T ANSWER YOUR QUESTION

Answer 2

Answer:

d=0/xy^2−x−2y

Step-by-step explanation:

Let's solve for d.

(y2−1)(d)x−2dy=0

Step 1: Factor out variable d.

d(xy^2−x−2y)=0

Step 2: Divide both sides by xy^2-x-2y.

d(xy^2−x−2y) / xy^2−x−2y=0xy2−x−2y

d=0/xy^2−x−2y

( I hope this was helpful) >;D