Question

Find the integral zeroes of the polynomial
x3 - 3x2 - 9x -5.​

Answer 1

Answer:

-1,-1,+5

Step-by-step explanation:

p(x) = x³ - 3x² - 9x - 5

By hit & trial ,

p(-1) = 0

So , x+1 is one of the three factors of p(x).

Now , on dividing p(x) by x+1 , we will get x² - 4x - 5 as quotient.

Now on factorising this quotient we get :-

x² - 4x - 5 = (x+1)(x-5)

So , p(x) = (x+1)(x+1)(x-5)

It's roots are -1,-1,+5

So , -1 , -1 , +5 are integral zeroes of p(x).

( Since , all of them are integers . )