Question

find the integration....​

Answer 1

Answer:

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Answer 2

Answer:

$\tt \int \frac{2 + {e}^{x} }{ {e}^{x} } dx$

$\tt= \int (\frac{2}{ {e}^{x} } + \frac{ {e}^{x} }{ {e}^{x} }) dx$

$\tt= \int \frac{2}{ {e}^{x} }dx + \int dx$

$\tt= 2 \int \: {e}^{ - x} dx + \int \: dx$

$\underline{\boxed{\tt= 2 {e}^{ - x} + x + c}}$

Where c is the integral constant.

Some Integral Identities:-

$\tt\int \: {x}^{n}dx = \dfrac{ {x}^{n + 1} }{n + 1} + c$

$\tt\int \: {e}^{x} dx = {e}^{x} + c$

$\tt\int \: {a}^{x} dx = \frac{ {a}^{x} }{ ln(a) } + c$

$\tt\int \: dx = x + c$

$\tt\int \ \frac{dx}{x} = ln |x| + c$

# Be brainly.