Question

find the inter cepts made by the following lines on the coordination axes 4× + 3y + 12= 0​

Answer 1

The line is 4x−3y=12

The intercept form is

3

x

−

4

y

=1

The intercepts are 4,3

The sum of square is 3

2

+4

2

=9+16=25

Explanation:

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