Question

Find the intercepts made by the line 4x – 9y +36 = 0 on the coordinate

axes.​

Answer 1

Answer:

x= -9 and y= 4

Step-by-step explanation:

4x-9y+36=0

to find x -intercepts put y=0

4x-9(0)= -36

4x= -36

x=

$x = \frac{ - 36}{4}$

x= -9

now, to find Y intercepts put x=0

4(0)-9y= -36

-9y= -36

$y = \frac{ - 36}{ - 9}$

y= 4

Answer 2

Answer:

The x-intercept and y-intercept of the given equation of line are found to be at (-9,0) and (0,4) respectively.

Step-by-step explanation:

The intercepts of any graphs are the points at which the graph crosses or intersects the coordinate axes.

The given equation of a straight line is:

$4x-9y+36=0$

Now, x-intercept is at the point where y=0, so substituting y=0 in the given equation, we get:

$4x-9(0)+36=0$

Simplifying it, we get:

$4x=-36$

Or we can say:

$x=-9$

The point for x-intercept will be at (-9,0).

Similarly, the y-intercept is at the point where x=0, so substituting x=0 in the given equation, we get:

$4(0)-9y+36=0$

Simplifying it, we get:

$-9y=-36$

Or we can say:

$y=4$

The point for y-intercept will be at (0,4).