Math, asked by sakshideshmukh90, 11 months ago

Find the intercepts made by the line on
the axes which pass through the point (5,-2) andhas slope 5/2​

Answers

Answered by mysticd
6

 Let \: a  \: point \: (x_{1},y_{1}) = (5,-2), \:and \\ Slope (m) = \frac{5}{2}

 \underline { \pink {  Point - Slope \:of \: \:the \:Equation }}

 \boxed { \orange { y - y_{1} = m(x-x_{1}) }}

\implies y - (-2) = \frac{5}{2} ( x - 5 )

 \implies 2(y - 2 ) = 5(x - 5)

 \implies 2y - 4 = 5x - 25

 \implies 0 = 5x - 25 - 2y + 4

 \implies 5x - 2y = 21

/* Divide each term by 21 , we get */

 \implies \frac{5x}{21} +  \frac{-2y}{21} = \frac{21}{21}

 \implies \frac{x}{\frac{21}{5}} + \frac{y}{\frac{-21}{2}} = 1

 Compare \: this \: with \\ \blue { Two \:intercepts \: form }

 \pink { \frac{x}{a} + \frac{y}{b} = 1 }

 Where , \blue { x - intercept = a },\\\blue { y - intercept = b}

Therefore.,

 \blue { x - intercept ( a )}\green { = \frac{21}{5}}

\blue { y - intercept = b}\green { = \frac{-21}{2}}

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