Question

find the interest and the amount of rupees 500 for 6 months at 4% per annum

Answer 1

expansion
{ ( \sqrt{x} - \frac{k}{ {x}^{2} }) }^{10}(x​−x2k​)10 
is 405 then k

Answer 2

Here is your answer⤵️

Principal = Rs 500

Rate of Interest = 4 p.c.p.a

Time = 6 months.

Interest = $\frac{P×R×T}{100}$

= $\frac{500×4×6}{100}$

= $5×4×6$

= 120

Interest = Rs 120


Amount = P + I

= 500 + 120

= Rs. 620.