Question

find the interest value of rupees 2000 due in 8 months at 12% simple interest​

Answer 1

Answer:

Let P be required value.

We know the formula,

A=P(1+

n

r

)

n.t

Given, A= Rs. 2000, r=10%, n=4 and t= 2

2

1

years

Therefore, 2000=P(1+

4

0.1

)

4×2.5

⇒2000=P×1.025

10

⇒2000=P×1.280085

⇒P=

1.280085

2000

⇒P= Rs. 1562.40

Answer 2

Answer:

0.075% is the value of rate of interest .

Step-by-step explanation:

Explanation:

Given , Simple interest = 12%

Time = 8 month

Principal value = 2000

Simple interest = $\frac{P .R .T}{100}$

Where , P  is stand for principal value , R is stand for  rate of interest and T is time .

Step1:

From the question we have ,

P = 2000

SI = 12% and Time(T) = 8 month .

SI = $\frac{P .R .T}{100}$

⇒12 = $\frac{2000 . R . 8 }{100}$  ⇒1200  = 16000 .R

⇒R = $\frac{1200}{16000}$ = 0.075%

Final answer:

Hence , the value of rate of  interest is 0.075% .

#SPJ2