Find the interior zero's of the polynomial x^3 + 3x^2 + x - 3
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4
Answer:
There is only one Zero
that is x=-1
p(x)=x³+3x²+x-3
p(-1)=(-1)³+3(-1)²+(-1)-3
p(1)=-1+3-1-3
p(1)=0
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