Find the internal surface area of a room whose dimensions are 4m×2.5m×6m
Answers
Answered by
3
Step-by-step explanation:
Internal surface is nothing but the total surface area
All the dimensions are different
Therefore, It is obvious that the figure is nothing but the 'CUBOID'
. '. total surface area of cuboid =2[lb+bh+hl]
= 2[(4*2.5)+(2.5*6)+(6*4)]
.'. =2 [10+15+24]
. '. = 2*49
. '. =98
.'. The internal surface are of the room is 98cm.sq.
Similar questions