Math, asked by bidyut1986, 10 months ago

find the intervals in which the function is decreasing or increasing​

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Answered by srijansarvshresth123
0

Answer:

f'(x)=

3 {x}^{2}  - 18x + 24 \geqslant  0 \\  {x}^{2}  - 6x + 8 \geqslant 0  \\  {x}^{2}  - 2x - 4x + 8  \geqslant 0 \\  x(x - 2) - 4(x - 2) \geqslant 0 \\ (x - 2)(x - 4) \geqslant 0

it is decreasing in range (2,4)

increasing in range (-infinite,2) U (4,infinite)

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