Question

find the intrest and amount if principal is rs 5000 . time 4 years and rate is 6% per amount​

Answer 1

Answer:

1st

year

Principal, P=Rs.5000

Time, T=1 year

Rate of interest ,R=6%

∴simple Interest, SI=

100

PTR

=

100

5000×10×6

=Rs.300

∴Amount=P+SI=Rs.5300

2nd year

Principal = Amount of 1st year=Rs.5300

Rate of interest =8%

Time =1 year

∴ Interest =

100

5300×1×8

=Rs.424

∴ Amount =Rs.(5300+424)=Rs.5724

The interest of 2nd year is the required compound interest. So, C.I=rs.424 and the required amount is Rs.5724

Answer 2

Answer :-

• The simple interest is Rs. 1200.
• The amount is Rs. 6200.

Step-by-step explanation:

To Find :-

• The Simple interest
• The amount

Solution:

Given that,

• Principal = Rs. 5000
• Time = 4 years
• Rate = 6% per annum

According the question,

• The Simple interest

As we know that,

Simple interest = ( P × R × T ) ÷ ( 100 )

Where,

• P = Principal
• R = Rate
• T = Time

=> ( P × R × T ) ÷ ( 100 )

=> ( 5000 × 6 × 4 ) ÷ 100

=> 50 × 6 × 4

=> 300 × 4

=> 1200

Therefore, The simple interest is Rs. 1200.

Now,

• The amount

As we know that,

Amount = Simple Interest + Principal,

=> Rs. 5000 + Rs. 1200

=> Rs. 6200

Therefore, The amount is Rs. 6200.