Find the inverse function of y=(3x+5)/(2x+3)
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y = (3x + 5)/(2x + 3)
y(2x + 3) = 3x + 5
2xy + 3y = 3x + 5
3y - 5 = 3x - 2xy
3y - 5 = x(3 - 2y)
x = (3y - 5)/(3 - 2y)
f⁻¹(x) = (3x - 5)/(3 - 2x)
y(2x + 3) = 3x + 5
2xy + 3y = 3x + 5
3y - 5 = 3x - 2xy
3y - 5 = x(3 - 2y)
x = (3y - 5)/(3 - 2y)
f⁻¹(x) = (3x - 5)/(3 - 2x)
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