Question

find the inverse of a matrix A using inverse of coefficient Matrix method: A= 2 3 10​

Answer 1

Answer:

x+y+z=6,2x+y+2z=10,3x+3y+4z=21A=⎝⎜⎜⎛123113124⎠⎟⎟⎞×=⎣⎢⎢⎡xyz⎦⎥⎥⎤,B=⎣⎢⎢⎡61021⎦⎥⎥⎤⇒∣A∣=1(−2)−1(2)+1(3)⇒∣A∣=−2−2+3=−1=0→Aisvertible⇒co−factorof∣A∣are⇒A1=−2,A2=−2,A3=3⇒A21=−1,A22=1,A

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