Question

® Find the largest 3-digit number which is divisible by

12, 15
18
and 20
leaving remainder 5 in each case.​

Answer 1

Answer:

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Step-by-step explanation:

ANSWER ::

The LCM of 12, 15,18,20 is 180

Now the largest 3 digit number is 999

If we divide 999 by 180 we get 5 as Quotient and 99 as Remainder

So the largest 3 digit number which is divisible by 180 is 999 - 99 = 900

So the required number is = 900 + 5 = 905

Answer 2

Answer:

905

Step-by-step explanation:

If we divide 999 by 180 we get 5 as quotient and 99 as remainder.

So, the largest 3 digit number which is divisible by 180 is 999-99=900.

So, the required number is 900+5=905