find the largest 4 digit number which when divided by 4 , 7 and 13 leaves a remainder 3 in each case
Answers
Answered by
19
L.C.M of 4,7 & 13=364
Now if 9999/364 = 27.469 so it is clear that 364*27 is very near to 9999 which completely divide all the given three no(4,7 & 13)
so finally our required Answer is 364*27 + 3 = 9831
Now if 9999/364 = 27.469 so it is clear that 364*27 is very near to 9999 which completely divide all the given three no(4,7 & 13)
so finally our required Answer is 364*27 + 3 = 9831
Answered by
13
hye
================================
largest 4 digit number = 9999
we have to Find the largest 4 digit number which when divided by 4 , 7 and 13 leaves a remainder 3 in each case
=>let us find the lcm of 4,7 and 13
= >prime factoristion of 4 = 2*2
= >prime factoristion of 7 = 7*1
= >prime factoristion of 13 = 13*1
=> 2 *7*13 *2
=>364
now let us divide 9999/364
=>27.4697...............
=>27 [approx]
=>27* 364
=>9828
now let us add 3 to it
=>9828 +3 = 9831
Therefore 9831 is the number.
===============================
hope it helps u...........
================================
largest 4 digit number = 9999
we have to Find the largest 4 digit number which when divided by 4 , 7 and 13 leaves a remainder 3 in each case
=>let us find the lcm of 4,7 and 13
= >prime factoristion of 4 = 2*2
= >prime factoristion of 7 = 7*1
= >prime factoristion of 13 = 13*1
=> 2 *7*13 *2
=>364
now let us divide 9999/364
=>27.4697...............
=>27 [approx]
=>27* 364
=>9828
now let us add 3 to it
=>9828 +3 = 9831
Therefore 9831 is the number.
===============================
hope it helps u...........
Similar questions