Math, asked by kundan85, 1 year ago

find the largest 4 digit number which when divided by 4 , 7 and 13 leaves a remainder 3 in each case

Answers

Answered by sanjeevnichaudhary
19
L.C.M of 4,7 & 13=364
Now if 9999/364 = 27.469 so it is clear that 364*27 is very near to 9999 which completely divide all the given three no(4,7 & 13)
so finally our required Answer is 364*27 + 3 = 9831
Answered by Raghav3333
13
hye

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largest 4 digit number = 9999

we have to Find the largest 4 digit number which when divided by 4 , 7 and 13 leaves a remainder 3 in each case

=>let us find the lcm of 4,7 and 13


= >prime factoristion of 4 = 2*2

= >prime factoristion of 7 = 7*1

= >prime factoristion of 13 = 13*1

=> 2 *7*13 *2

=>364 

now let us divide 9999/364

=>27.4697...............

=>27 [approx]

=>27* 364

=>9828

now let us add 3 to it

=>9828 +3 = 9831

Therefore 9831 is the number.

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hope it helps u...........


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