Find the largest 5 digit number divisible by 18,24 and 32
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solution:
By finding LCM of the 3 numbers, and applying euclid's division lemma with the smallest 6 digit number,then,subtracting the remainder,we can find rh largest 5 digit number divisible by all the 3 numbers.
2 I 18, 24, 32
L________
3 I 9, 12, 16
L________
3 I 3, 4, 16
L________
2 I 1, 4, 16
L________
2 I 1 , 2, 8
L________
2 I 1 , 1, 4
L________
2 I 1, 1, 2
L________
I 1, 1, 1
LCM= 2^{5} x 3^{2}=32x9=288
By using EUCLID DIVISION LEMMA,
We get,
a=bq+r
100,000=288(347)+64
100,000 - 64 = 99,936
∴The largest 5-digit number that is divisible by 18,24 and 32 is 99,936
HOPE IT HELPS..!
By finding LCM of the 3 numbers, and applying euclid's division lemma with the smallest 6 digit number,then,subtracting the remainder,we can find rh largest 5 digit number divisible by all the 3 numbers.
2 I 18, 24, 32
L________
3 I 9, 12, 16
L________
3 I 3, 4, 16
L________
2 I 1, 4, 16
L________
2 I 1 , 2, 8
L________
2 I 1 , 1, 4
L________
2 I 1, 1, 2
L________
I 1, 1, 1
LCM= 2^{5} x 3^{2}=32x9=288
By using EUCLID DIVISION LEMMA,
We get,
a=bq+r
100,000=288(347)+64
100,000 - 64 = 99,936
∴The largest 5-digit number that is divisible by 18,24 and 32 is 99,936
HOPE IT HELPS..!
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