Math, asked by zubairsaif57, 11 months ago

find the largest 7 digit no. that is divisible by 3331

Answers

Answered by yuktha182004
19

The largest 7 digit number is 9999662

Answered by tanika
19

Answer:

99,99,662

Step-by-step explanation:

Assuming you consider only positive numbers, the largest 7-digit number is 9,999,999, which is not divisible by 3,331 since the division 9,999,999 : 3,331 gives a quotient of 3,002 and a remainder of 337.

The same is true for 9,999,998 and for 9,999,997 and so on, each one producing, when divided by 3,331, remainders 336, 335 and so on. But if you subtract 337 from 9,999,999 you obtain 9,999,999 - 337 = 9,999,662 which is divisible by 3,331. In fact, 9,999,662 : 3,331 = 3,002 with no remainder.

Therefore, you can conclude that the largest 7-digit number divisible by 3,331 is 9,999,662

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