Find the largest and the shortest distance from the point 2, - 7 to the circle
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(a)2and28(b)4and20(c)3and27(d)5and25
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A)
Let S=x2+y2−14x−10y−151=0
Substituting the point (2,−7) in this equation, we get
S1=(2)2+(−7)2−14(2)−10(−7)−151=−56<0
∴P(2,−7) inside the circle
Radius of circle r=(−7)2+(−5)2+151−−−−−−−−−−−−−−−−√=15
Centre of circle (7,5)
CP=(7−2)+(5+7)2−−−−−−−−−−−−−−√=13
Shortest distance =PA=r−CP=15−13=2
Largest distance PB=r+CP=15+13=28
Hence (a) is the correct answer
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