Math, asked by kumarutsav2735, 10 months ago

Find the least number of cuts required which can cut a cube into 24 identical pieces?

Answers

Answered by trojan123
11

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The easiest case is slicing down through the top to get 6x4 vertical cuboids. This gives you 24 identical elongated cuboids with (6–1) + (4–1) or 8 cuts.

Systematically, how many ways can you factor 24 into 1, 2, or 3 factors? (3 for 3 dimensions)

24 x 1: slice the top in one direction 24 times. 23 cuts

12 x 2. Slice the top into 12 slices and the cut the middle once horizontally. 11 + 1 = 12 cuts

6 x 4: slice the top in 2 directions into 6 and 4 slices. 5+3 = 8 cuts

8x3: slice the top 8x3. 9 cuts

6x2x2: top into 6x2, then middle. 5+1+1 = 7 cuts

2x3x4: 2x3 on top, one in the middle. 1+2+3=6 cuts.

That’s all there is, so the winner is 6 cuts.

Answered by Anonymous
5

The solution: You can do it in a minimum of 6 cuts. Each face of the center cube must be cut once, and you can't possibly cut 2 faces of the same cube at the same time. Therefore, you need all 6 cuts to separate the 24 cubes.

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