find the largest four digit number that is exactly divisible by 8 ,15 and 40.
Answers
Answer:
Step-by-step explanation:
The largest four digit number is 9999.
The LCM of 8, 15 and 40 is 5*2*2*2*3 = 120.
Now we will find the largest 4 digit number by 120 and subtract the remainder from 9999.
Therefore, we will subtract 39 (remainder) from 9999 (largest four digit number).
9999-39 = 9960
Therefore, 9960 is the greatest four digit number that is exactly divisible by 8, 15 and 40.
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Determine the largest 3-digit number which is exactly divisible by 8, 10 and 12.
Answer:
Given
Three numbers 8,10 and 12
Find out
We need to find out the largest 3-digit number which is exactly divisible by 8, 10 and 12
Solution
To find out the largest 3-digit number which is exactly divisible by 8, 10 and 12
first let us calculate the L.C.M 8, 10 and 12
L.C.M of 8, 10, 12 = 2 x 2 x 2 x 3 x 5
Hence, LCM of 8, 10, 12 = 120
We have to find the greatest 3 digit multiple of 120
Therefore, the number is
120 x 8 = 960
120 x 10 = 1200
120 x 12 = 1440
The 1200 and 1440 are not 3-digit numbers.
Hence, the greatest 3- digit number exactly divisible by 8, 10 & 12 is 960.
Verification
Now, let us check whether 960 is divisible by 8, 10 and 12.
960 ÷ 8 = 120
960 ÷ 10 = 96
960 ÷ 12 = 80
So the greatest 3-digit number is 960.