Math, asked by strenbr, 9 months ago

find the largest four digit number that is exactly divisible by 8 ,15 and 40.​

Answers

Answered by kuladipanegi0316
2

Answer:

Step-by-step explanation:

The largest four digit number is 9999.

The LCM of 8, 15 and 40 is 5*2*2*2*3 = 120.

Now we will find the largest 4 digit number by 120 and subtract the remainder from 9999.

Therefore, we will subtract 39 (remainder) from 9999 (largest four digit number).

9999-39 = 9960

Therefore, 9960 is the greatest four digit number that is exactly divisible by 8, 15 and 40.

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Answered by ImpressAgreeable4985
1

Determine the largest 3-digit number which is exactly divisible by 8, 10 and 12.

Answer:

Given

Three numbers 8,10 and 12

Find out

We need to find out the largest 3-digit number which is exactly divisible by 8, 10 and 12

Solution

To find out the largest 3-digit number which is exactly divisible by 8, 10 and 12

first let us calculate the L.C.M 8, 10 and 12

L.C.M of 8, 10, 12 = 2 x 2 x 2 x 3 x 5

Hence, LCM of 8, 10, 12 = 120

We have to find the greatest 3 digit multiple of 120

Therefore,  the number is

120 x 8 = 960

120 x 10 = 1200

120 x 12 = 1440

The 1200 and 1440 are not 3-digit numbers.

Hence, the greatest 3- digit number exactly divisible by 8, 10 & 12 is 960.

Verification

Now, let us check whether 960 is divisible by 8, 10 and 12.

960 ÷ 8 = 120

960 ÷ 10 = 96

960 ÷  12 = 80

So the greatest 3-digit number is 960.

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