Question

Find the largest four-digit number which when divided by 4, 7 and 13 leaves a remainder of 3 in each case.

Answer 1

Answer:

so take LCM (4,7,13) = 364

Let largest 4digit number be= 9999

On dividing 9999 by 364

we get remainder= 171

so, 9999-171 =9828 +3 =9831

therefore, 9831 is the number.

Hope this help.

Cheers!!