Find the largest four-digit number which when divided by 4, 7 and 13 leaves a remainder of 3 in each case.
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Answer:
so take LCM (4,7,13) = 364
Let largest 4digit number be= 9999
On dividing 9999 by 364
we get remainder= 171
so, 9999-171 =9828 +3 =9831
therefore, 9831 is the number.
Hope this help.
Cheers!!
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