Question

Find the largest four-digits number which when divided by 4, 7 and 13
leaves a remainder of 3 in each case.
​

Answer 1

Answer:

heyyy,

So LCM ( 4,7,13) = 364

Largest 4 digit number = 9999

On dividng 9999 by 364 we get reaminder as 171

So 9999 - 171 = 9828 + 3 = 9831

Therefore 9831 is the number.

Step-by-step explanation:

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Answer 2

Answer:

Hey mate here we go

The numbers are 4,7,13 which leave 3 as remainder

LCM of 4,7,13 = 364

The largest 4 digit number is 9999

so

\begin{gathered} \frac{9999}{364} = 27.46 \\ now \: \\ 364 \times 27 = 9828 \\ remainder \: is \: 3 \: means \\ 9828 + 3 = 9831\end{gathered}

364

9999

=27.46

now

364×27=9828

remainderis3means

9828+3=9831

I hope this will helps you

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