find the largest no. that exactly divides 280 and 1245 leaves remainder 4 and 3 respectively.(ans: 138)
sagar736:
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280 - 4 = 276
1245-3 = 1242
by the euclids Division Algorithme
1242 = 276 *4 +138
276 = 138 *2 + 0
hence hcf or required no. is 138
i hope it is helpfull for you
1245-3 = 1242
by the euclids Division Algorithme
1242 = 276 *4 +138
276 = 138 *2 + 0
hence hcf or required no. is 138
i hope it is helpfull for you
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