Find the largest number of 3 digits which is a perfect square.
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961 (31^2)................
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The largest 3 digit number is 999
The number whose square is 999 is 31 is 961
Thus, the square of any number greater than 31 will be a 4 digit number
Therefore, the square of 31 will be the greatest 3 –digit perfect square
312 = 31 × 31 = 961
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