Find the largest number that divides 1251 , 9377and 15628 leaving remainder 1,2 and 3 respectively.
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Answered by
21
Firstly, subtract the remainders from the number .so,
1251 -1=1250;
9377-2=9375;
15628-3=15625
Then H.C.F of -
1250=5*5*5*5*2
9375=5*5*5*5*5*3
15625=5*5*5*5*5*5
so, H.C.F(1250,9375,15625)=5*5*5*5=625
Therefore, largest no. that divides 1257,9377,15628 is 625.
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1251 -1=1250;
9377-2=9375;
15628-3=15625
Then H.C.F of -
1250=5*5*5*5*2
9375=5*5*5*5*5*3
15625=5*5*5*5*5*5
so, H.C.F(1250,9375,15625)=5*5*5*5=625
Therefore, largest no. that divides 1257,9377,15628 is 625.
If it has helped you please mark it as brainliest .
Answered by
6
Answer:
625
Step-by-step explanation:
1251-1=1250
9377-2=9375
15628-3=15625
take the HCF of 1250, 9375 and 15625
1250= 5×5×5×5×2
9375=5×5×5×5×5×3
15625= 5×5×5×5×5×5×5
HCF = 5×5×5×5
= 625
∴, the largest number that divides 1251, 9377, 15628 leaving remainder 1,2,3 is 625
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