find the largest number that divides 2053 and 967 and leaves a remainder of 5 and 7 respectively
Answers
Answered by
16
Hi dear
(2053-5)=2048
(967-7)=960
So the required number= HCF of 2048 and 960.
Factors of 2048=
Factors of 960 =
Common =
HCF = 64
So,the required number = 64
(2053-5)=2048
(967-7)=960
So the required number= HCF of 2048 and 960.
Factors of 2048=
Factors of 960 =
Common =
HCF = 64
So,the required number = 64
Similar questions