find the largest number that divides 245 and 1029 leaving remainder 5 in each case
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HI
aim :to find the largest number that divides 245 and 1029 leaving remainder 5 in each case
=>245 - 5 = 240
=>1029 - 5 = 1024
so the numebrs are 240 and 1024
=> now hcf of 240 and 1024
=>240 = (2×2×2×2)×3×5
1024 = (2×2×2×2)×2×2×2×2×2×2
hcf = 16
hence 16 is the the largest number that divides 245 and 1029 leaving remainder 5 in each case
hope it helps u
:)
aim :to find the largest number that divides 245 and 1029 leaving remainder 5 in each case
=>245 - 5 = 240
=>1029 - 5 = 1024
so the numebrs are 240 and 1024
=> now hcf of 240 and 1024
=>240 = (2×2×2×2)×3×5
1024 = (2×2×2×2)×2×2×2×2×2×2
hcf = 16
hence 16 is the the largest number that divides 245 and 1029 leaving remainder 5 in each case
hope it helps u
:)
Raghav3333:
pls brainliest
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