find the largest number that divides 2623 and 2011 and leaves remainder 5 and 9
Answers
Answered by
9
Hii ,
Here is ur answer
2011–9 = 2002
2623–5 = 2618.
Factors of
2002 = 2 x7x11x13
2618 = 2x7x11x17
The HCF = 2 x7x11 = 154.
Check: 2011/154 = quotient = 13, and remainder = 9. Correct.
2623/154 = quotient = 17, and remainder = 5. Correct.
The number is 154.
Hope it will help u
Here is ur answer
2011–9 = 2002
2623–5 = 2618.
Factors of
2002 = 2 x7x11x13
2618 = 2x7x11x17
The HCF = 2 x7x11 = 154.
Check: 2011/154 = quotient = 13, and remainder = 9. Correct.
2623/154 = quotient = 17, and remainder = 5. Correct.
The number is 154.
Hope it will help u
Answered by
0
Hey Friend......☺
Here is your answer
first we will subtract-
2623-5, 2011-9
then we will find hcf of these no.s friend-
2618-2,7,11,172002-2,7,11,13
hcf is 154.
so friend now divide them-
2618/154=17 and if we take real number then answer is 17 and remainder 5.
2002/154=13 and if we take real number then answer is 9 and remainder 9.
Hoping it helps
Thanks.....
Here is your answer
first we will subtract-
2623-5, 2011-9
then we will find hcf of these no.s friend-
2618-2,7,11,172002-2,7,11,13
hcf is 154.
so friend now divide them-
2618/154=17 and if we take real number then answer is 17 and remainder 5.
2002/154=13 and if we take real number then answer is 9 and remainder 9.
Hoping it helps
Thanks.....
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