Math, asked by charu69, 1 year ago

find the largest number that divides 2623 and 2011 and leaves remainder 5 and 9

Answers

Answered by quest2
9
Hii ,
Here is ur answer

2011–9 = 2002

2623–5 = 2618.

Factors of

2002 = 2 x7x11x13

2618 = 2x7x11x17

The HCF = 2 x7x11 = 154.

Check: 2011/154 = quotient = 13, and remainder = 9. Correct.

2623/154 = quotient = 17, and remainder = 5. Correct.

The number is 154.

Hope it will help u
Answered by ShAiLeNdRaKsP
0
Hey Friend......☺

Here is your answer

first we will subtract-                                                                                  
2623-5,   2011-9

then we will find hcf of these no.s friend-
2618-2,7,11,172002-2,7,11,13

hcf is 154.

so friend now divide them-
2618/154=17 and if we take real number then answer is 17 and remainder 5.

2002/154=13 and if we take real number then answer is 9 and remainder 9.

Hoping it helps

Thanks.....
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