find the largest number that will divide 2053 and 967 and leaves a remainder of 5 and 7 respectively. (by steps)
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Here,
2053 - 5 = 2048
967 -7 = 960.
Therefore,
by EDL, we get
2048 = 2 × 960 + 128
960 = 7 × 128 + 64
128 = 2 × 64 + 0
Thus, the last divisor is 64.
Therefore, the largest number to divide 2053 & 967, leaving remainder 5 & 7 in each case respectively is 64.
Hope it helped.
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