on reduction with hydrogen 3.6g of an oxide of metal left 3.2g of the metal. if the atomic mass of the metal is 64 what would be the simplest formula of the oxide
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It is very simple,
In MO2, M contains 50% weight and other 50% is O2 means we know 50% is equal to 32, So the mass of M is 32,
In other case M contains 40% means 40% is equal to 32 of X?
we can calculate X now, So its is 48,
the formula for other oxide is MO3.
In actual these oxides are SO2 and SO3.
Hope you will find it useful.
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