Math, asked by nitin9351, 11 months ago


Find the largest number that will divide 398 435 and 542
l
eaving the remainder 7,11and15 respectively

Answers

Answered by shivani3155
0

Answer:

the largest number is 392 , 424 , 527

Step-by-step explanation:

398 , 435, 542 leaving a reminder 7 , 11 , 15

398 - 7 , 435 - 11 , 542 - 15

392, 424 , 527

the largest number which is divide 398, 435 and 527 is 392 , 424 and 527

Answered by Anonymous
2

Given :-

398 , 436 and 542

To Find :-

The largest number

Solution :-

Let’s assume the integer is x

According to the condition given in the question

⇒ xy+7 = 398

⇒  xz+11 = 436

⇒  xk+15 = 542

⇒ xy =391

⇒  xz = 425

⇒  xk = 527

⇒  17 × 23 = 391

⇒  17 × 25 = 425

⇒ 17 × 31 = 527

So, the largest possible integer that will divide 398,436,542 & leaves reminder 7,11 and 15 respectively was 17.

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