Find the largest number that will divide 398 435 and 542
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eaving the remainder 7,11and15 respectively
Answers
Answered by
0
Answer:
the largest number is 392 , 424 , 527
Step-by-step explanation:
398 , 435, 542 leaving a reminder 7 , 11 , 15
398 - 7 , 435 - 11 , 542 - 15
392, 424 , 527
the largest number which is divide 398, 435 and 527 is 392 , 424 and 527
Answered by
2
Given :-
398 , 436 and 542
To Find :-
The largest number
Solution :-
Let’s assume the integer is x
According to the condition given in the question
⇒ xy+7 = 398
⇒ xz+11 = 436
⇒ xk+15 = 542
⇒ xy =391
⇒ xz = 425
⇒ xk = 527
⇒ 17 × 23 = 391
⇒ 17 × 25 = 425
⇒ 17 × 31 = 527
So, the largest possible integer that will divide 398,436,542 & leaves reminder 7,11 and 15 respectively was 17.
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