Math, asked by bobby3114, 1 year ago

Find the largest number that will divide 398, 436 and 536 leaving re mainders 7, 11 and 15

wvaish: I feel this question is a bit wrong

wvaish: A number which divides 398,436,536 leaving remainders 7,11,15 doesn't exist

wvaish: If you make a small correction in replacing 15 with 9 then we can solve the problem

Answers

Answered by RAMZ

pls check the answers and comment

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Answered by snehitha2

Hi friend,

Your question might be

Find the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15

→398-7 = 391

436-11 = 425

542-15 = 527

The required number will be the HCF of 391,425 and 527.

391 = 17 × 23 × 1

425 = 17 × 5 × 5 × 1

527 = 17 × 31 × 1

HCF (391,425,527) = 17

Therefore,the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 is 17.

If your question is

Find the largest number that will divide 398, 436 and 536 leaving remainders 7, 11 and 15

Answer ↓

398-7 = 391

436-11 = 425

536-15 = 521

The required number will be the HCF of 391,425 and 521.

391 = 17 × 23 × 1

425 = 17 × 5 × 5 × 1

521 = 521 × 1

HCF (391,425,521) = 1

Therefore,the largest number that will divide 398, 436 and 536 leaving remainders 7, 11 and 15 is 1.

Hope it helps

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