Find the largest number that will divide 398, 436 and 542 leaving remainders 7, 11, and 15 respectively.
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Answer:
17
Step-by-step explanation:
Algorithm
398 – 7 = 391, 436 – 11 = 425, 542 – 15 = 527
HCF of 391, 425, 527 = 17
Thanks !
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