Math, asked by adarshkumar32, 10 months ago

find the largest number that will divide 623, 729 and 841 leaving remainders 3, 9 and one respectively​

Answers

Answered by dishabucha
18

Answer:

Step-by-step explanation:

623 - 3 = 620

729 - 9 = 720

841 - 1 = 840

Hcf of 620 n 720

720 = 620 × 1 + 100

620 = 100 × 6 + 20

100 = 20 × 5 + 0

Hcf = 20

Largest no. divide these is 20

Hope it helps uh

PlZ mark as brainliest

Answered by Satyavir11
7

Answer:

20

Step-by-step explanation:

623-3 , 729-9 , 841-1

620 , 720 , 840

HCF of 620 , 720 , 840

= 720 divided by 620 leaves remainder 100

= 620 divided by 100 leaves remainder 20

= 840 divided by 20 leaves remainder 0

= so, 20 is the HCF  AND the ans because if we divide 623 it will leave the remainder 3 , if divide 729 it will leave 9 and if 841 then 1

Similar questions