find the largest number that will divide 623, 729 and 841 leaving remainders 3, 9 and one respectively
Answers
Answered by
18
Answer:
Step-by-step explanation:
623 - 3 = 620
729 - 9 = 720
841 - 1 = 840
Hcf of 620 n 720
720 = 620 × 1 + 100
620 = 100 × 6 + 20
100 = 20 × 5 + 0
Hcf = 20
Largest no. divide these is 20
Hope it helps uh
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Answered by
7
Answer:
20
Step-by-step explanation:
623-3 , 729-9 , 841-1
620 , 720 , 840
HCF of 620 , 720 , 840
= 720 divided by 620 leaves remainder 100
= 620 divided by 100 leaves remainder 20
= 840 divided by 20 leaves remainder 0
= so, 20 is the HCF AND the ans because if we divide 623 it will leave the remainder 3 , if divide 729 it will leave 9 and if 841 then 1
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