find the largest number that you need to test as a divisor to determine whether each of the following is a prime member (a) 101. (b) 111 (c) 397
Answers
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The largest prime number for 101 and 111 is 7; for 397 it is 19.
To Find:
The largest number to check is the prime member of the given numbers.
Solution:
We need to find the prime numbers which are less than or equal to the square root of the given number.
(a) 101
√101 = 10.04
The prime number which is less than √101 are 2,3,5 and 7.
Hence,7 is the largest prime number of 101.
(b) 111
√111 = 10.53
The prime number which is less than √111 are 2,3,5 and 7.
Hence,7 is the largest prime number of 111.
(c) 397
√397 = 19.92
The prime number which is less than 1 or equal to √397 are 2,3,5,7,11,13,17, and 19.
Hence,19 is the largest prime number of 397.
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