Math, asked by cananyonehelp6117, 1 year ago

Find the largest number which divide 2053 and 967 leaving reminder 5 and 7 respectively

Answers

Answered by sonabrainly
2

it is given that on dividing 2053 by the required number there is a remainder of 5 .this mean that 2053 - 5 = 2048 is exactly divisible by required number . similarly,

967 - 7 = 960

the required number is the largest number satisfying the above property .

therefore ,it is the HCF of 2048 & 960

HCF of 2048 & 960 is 64 

hence required number is 64



Answered by dnavneetk9549
0

hi mate here is ur answer

2053 - 5 = 2048

967 - 7 = 960

finding hcf of 2048 and 960

we get ,64

hence the largest number that divides 2053,967 leaving remainder 5 and 7 is 64

hope it helps!!!

pls mark as brainliest

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