Find the largest number which divide 2053 and 967 leaving reminder 5 and 7 respectively
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it is given that on dividing 2053 by the required number there is a remainder of 5 .this mean that 2053 - 5 = 2048 is exactly divisible by required number . similarly,
967 - 7 = 960
the required number is the largest number satisfying the above property .
therefore ,it is the HCF of 2048 & 960
HCF of 2048 & 960 is 64
hence required number is 64
Answered by
0
hi mate here is ur answer
2053 - 5 = 2048
967 - 7 = 960
finding hcf of 2048 and 960
we get ,64
hence the largest number that divides 2053,967 leaving remainder 5 and 7 is 64
hope it helps!!!
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