Math, asked by animesh4india, 8 months ago

Find the largest number which divide 2312, 1454 and 628 leaving remainders 4, 2 and 8
respectively.

Answers

Answered by vermavansh173

1

Answer:

Step-by-step explanation:

2312-4=2308

1454-2=1452

628-8=620

lcm ==>129859620

Answered by guptapneumatics2

0

Answer:

2

Step-by-step explanation:

let, the numbers be :- 2312 ,1454,628

remainder:- 4,2,8

2312-4 =2308

1454-2 = 1452

628-8=620

LCM of 620,1452,2308=2,077,753,920

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