Math, asked by dharams766, 12 hours ago

Find the largest number which divides 1386,1458 and 1629 leaving remainder 6,3 and 9 respectively

Answers

Answered by pinakiparbatihembram
6

Answer:

First we will subtract 6,3 and 9 from 1386,1458 and 1629 respectively.

1386-6 =1380

1458-3=1455

1629-9= 1620

Then, HCF of 1380, 1455, 1620 = 15

Therefore, 15 is the largest number which divides 1386,1458 and 1629 leaving remainder 6,3 and 9 respectively.

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