Question

Find the largest number which divides 2053 and 967 and leaves a remaindet of 5 and 7 respectively

Answer 1

Hii friend,

2053 - 5 = 2048

967- 7 = 960

Prime factorisation of 2048 = 2 × 2 × 2 × 2 × 2 × 2 × 2 ×2 × 2 × 2 × 2.

Prime factorisation of 960 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 5.

HCF of 2048 and 960 = 2 × 2 × 2× 2 × 2 × 2 = 64.

HENCE,

The required Number = 64

HOPE IT WILL HELP YOU..... :-)