Question

find the largest number which divides 220,328,428 leave remainder 4 in each case​

Answer 1

Step-by-step explanation:

To find the largest number which exactly divides 280 and 1245 leaving remainders 4 and 3 respectively, we subtract 4 and 3 from 280 and 1245.

280−4=276

1245−3=1242

276=2×2×3×23

1242=2×3×3×3×23

HCF=2×3×23=138

Therefore, the largest number which exactly divides 280 and 1245 leaving remainders 4 and 3 respectively is 138

Answer 2

Answer:

Subtract 5 from each number and then find the H.C.F.

245−5=240 and 1029−5=1024

H.C.F(240,1024) by Euclid's division lemma a=bq+r

a=1024,b=240

1024=240×4+64

240=64×3+48

64=48×1+16

48=16×3+0

H.C.F=16

Hence the required number =16

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Step-by-step explanation:

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